Question

Facetimi si mie unu dintre axercitiile din poza va rog

Answer 1

d)$(1+i)^8=((1+i)^2)^4=(1+2i+i^2)^4=(2i)^4=16i^4=16 \\ ( 1+i)^{36}=( (1+i)^2)^{18}= 2^{18} i^{18}= 2^{18}(-1)=- 2^{18} \\ (2+5i)^2+(2-5i)^2=4+20i+25i^2+4-20i+25i^2=8-50=-42 \\ (3+4i)(3-4i)( \sqrt{3}-i)( \sqrt{3}+i)=(9-16i^2)(3-i^2)=25*4=100$