Question

fără punctul c) (cât de repede va rog. Mult) ​

Answer 1

Explicație pas cu pas:

$d) \frac{72}{77} \times ( \frac{2}{36} + \frac{5}{12} + \frac{14}{48} ) - \frac{10}{35} = \\ \frac{72}{77} \times ( \frac{8 + 60 + 42}{144} ) - \frac{10}{35} = \\ \frac{72 {}^{(72} }{77 {}^{(11} } \times \frac{110 {}^{(11} }{144 {}^{(72} } - \frac{10}{35} = \\ \frac{10}{14} - \frac{10}{35} = \frac{50 - 20}{70} = \frac{30 {}^{(10} }{ {70}^{(10} } = \frac{3}{7} \\ \\ e) \frac{10}{19} \times [ \frac{3}{6} + \frac{5}{35} - ( \frac{21}{9 {}^{(3} } \times \frac{6 {}^{(3} }{20} - \frac{9}{15} )] = \\ \frac{10}{19} \times [ \frac{3}{6} + \frac{5}{35} - ( \frac{42}{60} - \frac{9}{15} )] = \\ \frac{10}{19} \times [ \frac{3}{6 } + \frac{5}{35} - ( \frac{42 - 36}{60} )] = \\ \frac{10}{19} \times ( \frac{3}{6} + \frac{5}{35} - \frac{6}{60} ) = \\ \frac{10}{19} \times ( \frac{210 + 60 - 42}{420} ) = \\ \frac{10 {}^{(10} }{19 {}^{(19} } \times \frac{228 {}^{(19} }{420 {}^{(10} } = \frac{12 {}^{(6} }{42 {}^{(6} } = \frac{2}{7}$

sper că te-am ajutat