Question

Fenol monohidroxilic cu NE=7 ce contine 10,126% O. Imi puteti spune cum aflu care e?

Answer 1

pai N.E. = 7 => structura cu naftalina ± catena laterala + o grupare OH

formula generala = CnH2n-12O

100% ........................ 10,126% O

miu ........................... 16g O

=> miu = 158 g/mol

=> 14n-12+16 = 158 => n = 11

=> C11H10O

=> CH3-C10H6-OH