Question

Fie a =[(2^3)^2-2019^0]:3^2^1^2019 - (1^3^4 +2^2^1^2020)
b=81x11^4 - 33^4 +1, Calculati (a-b)^2019

Answer 1

a =[(2³)²  - 2019⁰ ]÷3²^¹^²⁰¹⁹ - (1³^⁴ +2^²^¹^²⁰²⁰) =
= ( 2⁶ - 1) ÷ 3² -(1+2²)= ( 64 - 1) ÷ 9 -(1+4)= 63÷9 - 5= 7-5= 2

b=81x11⁴  - 33⁴ +1= 3⁴×11⁴ - 33⁴ +1= 33⁴ -33⁴ +1= 0+1=1


(a-b)²⁰¹⁹= (2-1)²⁰¹⁹ = 1²⁰¹⁹ =1