Question

Fie A(4,5) B(6,1) determinati modulul vectorului AB​

Answer 1

$A(4,5)$

$B(6,1)$

$\vec{AB}=(x_{B}-x_{A})\vec{i}+(y_{B}-y_{A})\vec{j}$

$\vec{AB} = (6 - 4) \vec{i} + (1 - 5) \vec{j}$

$\vec{AB} = 2 \vec{i} - 4 \vec{j}$

$|\vec{AB}| = \sqrt{ {2}^{2} + {( -4 )}^{2} } = \sqrt{4 + 16} = \sqrt{20} = 2 \sqrt{5}$