Question

fie a multimea solutiilor reale ale ecuatiei 4x^2+3x-10=0

Answer 1

Buna!
e ecuatie de gradul 2 asadar calculam delta.
Δ = 9 + 4*10*4 = 169 =$13^{2}$
asadar, $x_{1}$ = $\frac{-3 + \sqrt{169} }{8}$ =$\frac{10}{8}$ = $\frac{5}{4}$  
si $x_{2}$ = $\frac{-3 - \sqrt{169} }{8}$ =$\frac{-16}{8}$= - 2
deci, A = { -2 , $\frac{5}{4}$ }

Answer 2

4x²+3x-10=0
∆=b²-4ac
∆=3²-4·4·(-10)
∆=9+160=169
x1=(-b-√∆)/2a=(-3-13)/8=-16/8=-2
x2=(-b+√∆)/2a=(-3+13)/8=10/8=5/4
a={-2; 5/4}