Question

Fie a= radical de ordin 3 din -54 + rad de ordin 3 din 16 + rad de ord 3 din 2

Answer 1

a= ³√-54 +³√16+³√2 = ³√-2x27 +³√2^4 +³√2 =³√-2x3^3 + 2³√2+³√2 = -3³√2+3³√2=0

Answer 2

$\sqrt[3]{-54}+ \sqrt[3]{16}+ \sqrt[3]{2}= \sqrt[3]{-2*27}+ \sqrt[3]{2*8}+ \sqrt[3]{2}= \\ =-3 \sqrt[3]{2}+2 \sqrt[3]{2}+ \sqrt[3]{2}=-3 \sqrt[3]{2}+3 \sqrt[3]{2}=0$