Question

Fie AB si CD doua trepte concurente in punctul O.Daca m(AOC)=80°,aflati m(BOD),m(Boc),m(AOD).

Answer 1

M(dob)=80
M(cob)=(360-80x2):2=100=m(aod)

Answer 2

m(<AOC)+m(<COB)+m(<BOD)+m(<DOA)=360°
m(<AOC)=m(<BOD)=80° (opuse la varf)
=> 160°+m(<COB)+m(<DOA)=360°
m(<COB)=m(<DOA)=360°-160°=200° (opuse la varf) =>m(<COB)=100° si m(<DOA)=100°

Sper ca te-am ajutat! =)