Question

fie abc si mnp doua triunghiuri cu m(A)=90*=m(M).Daca:
a)BC=NP=10cm,AB=MN=7cmsi perimetrul ABC=23cm,aflati MP
b)BC=NP=11cm,AC=MP=9cm si perimetrul MNP=27cm, aflati AB
c)BC=NP=13cm , AB=8cm,MP=10cm si perimetrul MNP=31cm,artati ca ABC=MNP
d)BC=NP=14 cm , AC=7 cm , MN=12 cm si perimentrul MNP=33 cm,aratati ca ABD=MNP.

Answer 1

a) P=AB+BC+AC
23=7+10+AC
23=17+AC
AC=23-17
AC=6
AC=MP => MP=6 cm

b)P=MN+MP+NP
27=MN+11+9
27=MN+20
MN=27-20
MN=7
MN=AB => AB=7 cm

c)AC=MP
PABC=8+13+10
P=31cm  => ABC=MNP

d)PABC= AB+AC+BC
AB=MN
P=12+7+14
P=33 cm  => ABC=MNP