Question

"Fie dreptABCD,AD=12 cm.M apartine laturii AB,astfel AM/MB=4/3,iar m(

Answer 1

A MBCD=(BM+CD)BC/2   (trapez dreptunghic)
ΔAMD triunghi dreptunghic, tg D=AM/AD, √3/2=AM/10, AM=10√3/2=5√3/2

AM/MB=4/3, AM/(MB+AM)=4/(4+3), AM/AB=4/7, AB=7AM/4=35√3/4
BM=3/4AM=15√3/4
A=(15√3/4+35√3/4)x10/2=5√3/2