Question

Fie f:R->R,f (x)=4x-2.Calculați f (0);f (1/2);f (1/3);..........f (1/10)​

Answer 1

Răspuns:

Explicație pas cu pas:

f:R->R, f (x)=4x-2        4x-2=0   x=1/2

f(0)=0-2=-2

f(1/2)=4×1/2-2=2-2=0

f(1/3)=4×1/3-2=(4-6)/3=-2/3

f(1/4)=4×1/4-2=1-2=-1

f(1/5)=4×1/5-2=(4-10)/5=-6/5

f(1/6)=4×1/6-2=(4-12)/6=-8/6=-4/3

f(1/7)=4×1/7-2=(4-14)/7=-10/7

f(1/8)=4×1/8-2=(4-16)/8=-12/8=-3/2

f(1/9)=4×1/9-2=(4-18)/9=-14/9

f(1/10)=4×1/10-2=(4-20)/10=-16/10=-8/5