Question

fie f:r->r,f(x)=(m^2-1)x+m+1. aratati ca f(1)>sau egal -1/4

Answer 1

$f(x)=(m^2-1)x+m+1 \\ \\f(1)=m^2-1+m+1=m^2+m\geq-\frac{1}{4} \\\\m^2+m+\frac{1}{4}\geq 0\\ \\(m+\frac{1}{2})^2\geq0~(Adevarat)$