Question

Fie f:R->R, f(x) = $\left \{ {{\frac{1}{x^{2}+1}},x\leq0 \atop {-2x+1},x\ \textgreater \ 0} \right.$ . Determinati ecuatia tangentei $G_{f}$ in punctul A(-1;$\frac{1}{2}$}

Answer 1

Poza conține rezolvarea.