Question

fie functia f ,g :R -R , f(x)=3x+3 si g(x)=x²+4x .a)calculati (f o g)(4) b)rezolvati ecuatia (f o g )(x)=0 va roggg am nevoie urgent ,o persoana serioasa nu pusti care doar stiu sa fure puncte ​

Answer 1

a) (f○g)(x) = f(g(x)) = 3g(x)+3 = 3(x²+4x)+3 = 3x²+12x+3

=> (f○g)(4) = 3·4²+12·4+3 = 99

b) (f○g)(x) = 0

3x²+12x+3 = 0 |:3

x²+4x+1 = 0

delta = 4²-4·1·1 = 16-4 = 12

x1 = (-4+√12)/2 = (-4+2√3)/2 = -2+√3

x2 = (-4-√12)/2 = (-4-2√3)/2 = -2-√3