Question

Fie functia f:R-->R , F(x)= -2x+$\sqrt{6}$ . Aratati ca a = $\frac{f( \sqrt{3} )-f( \sqrt{2} )}{ \sqrt{2}- \sqrt{3} }$ ∈ N

Answer 1

$\frac{(-2 \sqrt{3}+ \sqrt{6}+2 \sqrt{2} - \sqrt{6} )}{ \sqrt{2}- \sqrt{3} }$

Answer 2

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