Question

fie functia f:R la R, f(x)=ax+b-√9$x^{2}$-30x+25
pt care valori reale a si b punctele A(2;2), B(1;-1) APARTINE GRAFICUL FUNCTIEI F?

Answer 1

f(1)=1⇒a+b-√9-30+25=1
a+b=9⇒b=9-a
f(2)=2⇒2a+b-4√9-60+25=2
2a+b=41
2a+9-a=41
3a=32
a=16
b=-7