Question

Fie Gg graficul functiei g:R->R
g(x)=ax-2
Aflati numarul real "a" daca:
a) A(2;-4)∈Gg
b)B(-4,6)∈Gg
c)C(3,5)∈Gg

Answer 1

g(x)=ax-2 inlocuim si avem:
a)g(2)=-4
a*2-2=-4
a*2=-4+2
a*2=-2
a=-2/2
a=1
b)g(-4)=6
a*(-4)-2=6
a*(-4)=6+2
a*(-4)=8
a=8/(-4)
a=-2
c)g(3)=5
a*3-2=5
a*3=5+2
a*3=7
a=7/3