Question

fie multimea A=(—2, —1, 0, 1, 2) si B=(X|X =2a+1, a€A​

Answer 1

Răspuns:

A={—2, —1, 0, 1, 2}

B={x |x = 2a+1 , a€A}

a= -2

x=2a+1

x=2(-2)+1

x= -4+1

x= - 3

a= -1

x=2a+1

x=2(-1)+1

x=-2+1

x= -1

a=0

x=2a+1

x=2×0+1

x=1

a=1

x=2a+1

x=2×1 +1

x=3

a=2

x=2a+1

x= 2×2+1

x=4+1

x= 5

B={ - 3, - 1 , 1 , 3, 5}

Explicație pas cu pas: