Question

fie multimea A={ -8/4 ; -3/-0,5 ; 78/-13 ; 7/4 ; 6^2:3^2 ; (-3)^0 } Determinati A intersectat cu N ; A intersectat cu Z si A \ Z

Answer 1

Bună!

  (★‿★)

A={ -8/4 ; -3/-0,5 ; 78/-13 ; 7/4 ; 6^2:3^2 ; (-3)^0 }

$-\frac{8}{4}=-2$

$\frac{-3}{-0,5}^{(-1} =\frac{3}{\frac{5}{10} } =3*\frac{10}{5} =\frac{30}{5} =6$

$\frac{78}{-13} =-6$

$6^{2} :3^{2} =2^{2} =4$

$(-3)^{0} =1$

⇒ A={-2, 6, -6, 7/4, 4, 1}

Rezolvare:

A∩N={1, 4, 6}

A∩Z={-6, -2, 1, 4, 6}

A\Z={7/4}

#copaceibrainly