Question

Fie multimea M={-3,-5/2,0,2,5/2,3}.Determinați:​

Answer 1

a) M∩ℕ={0,2,3}

b)M-ℕ={-3,-5/2,5/2}

c)M∪ℕ= {-3,-5/2,0,1,2,5/2,3,4...}

d)M∩ℤ={-3,0,2,3}

e)M∩ℤ-ℕ={-3,0,2,3}-ℕ={-3}

f) M∩ℚ-ℤ=M-ℤ={-5/2,5/2}

Answer 2

$\it a)\ \ M\cap \mathbb{N}=\{0,\ \ 2,\ \ 3\}\\ \\ b)\ \ M- \mathbb{N}=\{-3;\ \ -\dfrac{5}{2}\ \ \dfrac{5}{2}\}$

$\it c)\ \ M\cup \mathbb{N}=\mathbb{N}\cup \{-3;\ \ -\dfrac{5}{2};\ \ \dfrac{5}{2}\}\\ \\ d)\ \ M\cap \mathbb{Z}= \{-3;\ \ 0;\ \ 2;\ \ 3\}\\ \\ e)\ \ M\cap \mathbb{Z}-\mathbb{N}= \{-3\}\\ \\ f)\ \ M\cap \mathbb{Q}-\mathbb{Z}= \{ -\dfrac{5}{2};\ \ \dfrac{5}{2}\}$