Question

Fie multimile A={0,1,2} so B={x=2^{a} + a, unde a ∈ A}. Enumerati elementele multimii B.

Answer 1

Răspuns:

A={0,1,2}

B={x=2^a+a}

a=0

x=2⁰+0=1+0=1

a=1

x=2¹+1=2+1=3

a=2

x=2²+2=4+2=6

B={1,3,6}

Explicație pas cu pas:

Answer 2

$A = \{0,\,1,\,2\}$

$\begin{aligned}B&= \{x = 2^a+a,\,\,a\in A\}\\ & =\{2^{0}+0,\, 2^{1}+1,\, 2^2+2\}\\ &=\{1+0,\, 2+1,\, 4+2\}\\ &=\{1,\,3,\, 6\}\end{aligned}$

⇒ B = {1, 3, 6}