Question

Fie n apartine N. Determinati numarul natural p care are proprietatea : p la patrat =4n(n-1) +1

Answer 1

[tex]p^2=4n(n-1)+1\\ p^2=4n^2-4n+1\\ p^2=(2n-1)^2|\sqrt{ }\\ |p|=|2n-1|\\ \text{Deoarece }p,n\in \mathbb{N}\Rightarrow p=2n-1[/tex]