Question

fie nr intregia=-8 b=+6 c=-25 si d=+36 calculati a-b; d-b; -d-b; b-(-c); (-d)-(-a); (-a)-(-b); b+a-d; a-c; c-d; a-(-b); a-(-c); (-a)-(-c);va rog frumos 10 puncte

Answer 1

a-b=-8-6=-14
d-b=36-6=30
-d-b=-36-6=-42
b-(-c)=6-25=-19
(-d)-(-a)=-36-8=-44
-(a)-(-b)=8+6=14
b+a-d=5-8-36=-39
a-c=-8+25=16
c-d=-25-36=-61
a-(-b)=-8+6=-2
a-(-c)=-8-25=-33
(-a)-(-c)=8-25=-17