Question

Fie numărul a = 8+2[(3•5² -2² •18:9+11•3):4] aratati ca este divizibil cu 2

Answer 1

Răspuns:

a = 8+2[(3•5²-2²•18:9+11•3):4] = 8+2[(3•25-4•2+33):4] =

= 8+2[(75-8+33):4] = 8+2(100:4) = 8+2•25 = 8+50 =

= 58 ( fiind numar par, este divizibil cu 2)

Explicație pas cu pas:

Sper ca te-am ajutat :)

Answer 2

 

$\displaystyle\bf\\a=8+2[(3\cdot5^2-2^2\cdot18:9+11\cdot3):4]\\\\a=8+2[(3\cdot25-4\cdot18:9+11\cdot3):4]\\\\a=8+2[(3\cdot25-4\cdot18:9+11\cdot3):4]\\\\a=8+2[(75-72:9+33):4]\\\\a=8+2[(67+33):4]\\\\a=8+2[100:4]\\\\a=8+2\cdot25\\\\a=8+50\\\\\boxed{\bf~a=58~\vdots~2}$