Question

Fie numerele a=37-√1,44·10² si b=42 plus 3√1,6²·10².Aflati raportul dintre media geometrica si aritmetica a numerelor si b

Answer 1

a = 37 - radical (1,44×10^2) = 37 - 1,2×10 = 37 - 12 = 25

b = 42 + 3 radical (1,6^2×10^2) = 42 + 3×1,6×10 = 42 + 48 = 90

Media geometrica(a,b) = radical (25×90) = radical(5^2×3^2×2×5) = 15 radical 10

Media aritmetică (a,b) = (25+90)/2 = 115/2

Media geometrica/media aritmetică = (15 radical 10)/(115/2) = 15 radical 10 × 2/115 = 6/23 × radical 10