Question

Fie numerele: A= 4√18 - 3√50 + 6√72 - √162 si B= 4√24 - 5√54 - 2√486 + √216.
Sa se afle A·B si A/B

Answer 1

$[tex](x+ \sqrt{5} )^{2} = x^{2} +2x \sqrt{5} + \sqrt{5} ^2= x^{2} +2 \sqrt{5} +5$