Question

Fie numerele a = 8¹³×4³÷16¹¹ și b= 27¹⁰×81²÷9¹⁹ .Calculați (a+b)⁴ ; (a-b)²⁰¹⁹. Urgent pls​

Answer 1

Răspuns:

a=8¹³× 4³÷16¹¹

(2³)¹³×(2²)³÷(2⁴)¹¹

2³⁹×2⁶÷2⁴⁴=

2⁴⁵÷2⁴⁴= 2¹=2

b= 27¹⁰×81²÷9¹⁹=

(3³)¹⁰×(3⁴)²÷(3²)¹⁹=

3³⁰×3⁸÷3³⁸=

3³⁸÷3³⁸=1

(a+b)⁴=(2+1)⁴=3⁴=81

(a-b)²⁰¹⁹=(2-1)²⁰¹⁹=1²⁰¹⁹=1

Answer 2

Răspuns:

a=8¹³·4³:16¹¹=(2³)¹³·(2²)³:(2⁴)¹¹=2³ˣ¹³·2²ˣ³:2⁴ˣ¹¹=2³⁹·2⁶:2⁴⁴=2³⁹⁺⁶:2⁴⁴= 2⁴⁵⁻⁴⁴=2¹=2

b= 27¹⁰·81²:9¹⁹=(3³)¹⁰·(3⁴)²:(3²)¹⁹=3³ˣ¹⁰·3⁴ˣ²:3²ˣ¹⁹=3³⁰·3⁸:3³⁸=3³⁸:3³⁸=1

(a+b)⁴=(2+1)⁴=3⁴=81

(a-b)²⁰¹⁹=(2-1)²⁰¹⁹=1²⁰¹⁹=1