Question

Fie numerele reale x, y ≠ 0. Calculati :
$2x \times 3y + 3xy \times 2 + x \times ( - 4y) = \\ 3x^{2} \times y + 5x \times ( - 2xy) + 2xy \times 2x = \\ (3xy)^{2} + {4x}^{2} \times ( - 2y ^{2} ) + 2x \times 3xy^{2} - xy \times ( - 3xy) =$
3x*(2y)³+4xy*3y²-xy²*2y-3xy³*2=
9x⁴y³:(3x²y) +(2xy)²+10x³y²:(-2x)=
7x²:x*2y+3y⁴:(3y³)*(-2x)+6*(-2xy
$3x \times (2y)^{3} +4xy \times 3y ^{2} -xy ^{2} \times 2y-3xy ^{3} \times 2= \\ \ \textless \ br /\ \textgreater \ 9x ^{4} y ^{3} :(3x^{2} y) +(2xy) ^{2} +10x ^{3} y^{2} :(-2x)= \\ \ \textless \ br /\ \textgreater \ 7x ^{2} :x \times 2y+3y ^{4} :(3y )^{3} ) \times (-2x)+6 \times (-2xy).$
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Answer 1

atasex rezolvarea completa a exercitiilor :)