Question

fie numerele x=93*20/310-324/36si y=32 *34-32*4/32+30-303
comparati numerele
repeeeeeede va rog

Answer 1

 x=93*20/310-324/36=93*2/31-9=3*2-9=6-9=-3
 y=32*34-32*4/32+30-303=1088-4+30-303=811
y > x

Answer 2

[tex]x=93 \cdot \frac{20}{310} -\frac{324}{36} \ \textgreater \ y=32\cdot(34-32)\cdot\frac{4}{32}+30-303\\ x=93\cdot\frac{2}{31}-9 \ \textgreater \ y=2\cdot4+30-303\\ x=3\cdot2-9\ \textgreater \ y=8+30-303\\ x=6-9\ \textgreater \ y=38-303\\ x=-3\ \textgreater \ y=-265\\\\ Sper\ ca\ te-am\ ajutat! :)[/tex]