Question

Fie numerele x y si z .prin impartirea nr y la nr x se obtine catul 3 si restul 5,iar prin impartirea nr z la nr y se obtine catul 4 si restul 80.Aflati cele 3 nr stiind ca suma lor este521

Answer 1

Răspuns:

x+y+z=521

y:x=3 rest 5=>y=3x+5

z:y=4 rest 80=>z=4y+80=>z=4(3x+5)+80=>z=12x+20+80=>z=12x+100

x+3x+5+12x+100=521

16x=521-105

x=416:16

x=26

y=3·26+5=>y=83

z=12·26+100=>z=412

Answer 2

Răspuns:

Y :x=3,r5. Y+x+z=521

Z:y=4,r80

Y=3x+5

Z=4y+80

3x+5+x+4y+80=521

3x+5+x+4*3x+5+80=521

4*7x+5+5+80=521

28x+90=521/-90

28x=431

Faza e ca da cu rest =p