Question

Fie O punctul de intersectie a diagonalelor dreptunghiului ABCD daca P abc= 48cm P abo = 36cm P bco = 32 cm . Alfati a)BC b) AB c)BD

Answer 1

PΔABC = AB + BC + AC =48cm (1)
PΔABO = AB + BO+OA =36 cm (2)
PΔBCO= BC+ CO +OB = 32 cm (3)
BC ?
AB ?
BD ?
BO +OA =AC
CO + OB = AC
 (2)AB + AC =36⇒ AB = 36- AC
(3) BC + AC = 32⇒ BC = 32-AC
(1) 36 -AC + 32 - AC + AC =48
 36 +32 - 48 = AC
 68 -48 =AC
20 = AC = BD
AB = 36 -AC
AB = 36-20 
AB -16 cm 
BC = 32-AC
BC = 32 - 20
BC = 12cm