Question

Fie paralelogramul ABCD cu perimetrul de 120 cm. Aflați laturile în fiecare caz în parte:
a) AB= 28 cm b) AB=2xBC
c) AB=AD-8 d) BC=AB/3 e)AB=ADx4+5 f) BC=20% din AB


ESTE URGENT VA DAU COROANA PLS REPEDE

Answer 1

Răspuns:

P ABCD =120cm

a) AB +BC+CD+AD=120cm

AB=CD=28cm

BC=AD=x cm

28+ x+28+x=120

56+2x=120

2x=64

x=32

BC=AD=x=32cm

b) AB+BC+CD+AD=120cm

AB=CD=2BC

BC=AD

2BC+BC+2BC+BC=120

6BC=120

BC=AD=20cm

AB=CD=2•20=40cm

c)AB+BC+CD+AD=120

AB=CD=AD-8

BC=AD

AD-8+AD+AD-8+AD=120

4AD-16=120

4AD=136

AD=BC=34cm

AB=CD=AD-8=34-8=26cm

d)AB+BC+CD+AD=120

BC=AB/3 rezulta ca AB=3BC=CD

BC=AD

3BC+BC+3BC+BC=120

8BC=120

BC=AD=15cm

AB=CD=3BC=3•15=45cm

e)AB+BC+CD+AD=120

AB=CD=4AD+5

BC=AD

4AD+5+AD+4AD+5+AD=120

10AD+10=120

10AD=110

AD=BC=11cm

AB=CD=4•11+5=44+5=49cm

f)AB+BC+CD+AD=120

BC=20%•AB=20/100•AB=2/10•AB=1/5•AB=AB/5

BC=AB/5 rezulta ca, AB=5BC=CD

BC=AD

5BC+BC+5BC+BC=120

12BC=120

BC=AD=10cm

AB=CD=5BC=5•10=50cm