Question

Fie polinomul P(x)=x²-3x+4. Sa se calculeze P( -√2)

Answer 1

P(-rad2)=(-rad2)^2-3*(-rad2)+4=2+3rad2+4=6+3*rad2=3(2+rad2)

Answer 2

$P(- \sqrt{2}) = (- \sqrt{2})^2 - 3 *(- \sqrt{2} ) + 4 = 2+3 \sqrt{2} +4 = 6+3 \sqrt{2}$