Question

Fie proportiile :

b supra 3 = 2 supra a si 2 supra a = 3 supra a+c . Calculati bc.

Va rog ajutatima !!

Answer 1

[tex] \displaystyle \frac{b}{3} = \frac{2}{a}=\ \textgreater \ \frac{1}{a}= \frac{b}{6} \\ \frac{2}{a} = \frac{3}{a+c} =\ \textgreater \ \frac{a+c}{a} = \frac{3}{2} =\ \textgreater \ 1+ \frac{c}{a} = \frac{3}{2}=\ \textgreater \ \frac{c}{a} = \frac{1}{2}\\ c\cdot \frac{1}{a}= \frac{1}{2} \\ c\cdot \frac{b}{6} = \frac{1}{2} \\ bc=3[/tex]