Question

FIE TRIUNGHIUL ABC CU UNGHIUL A=90 GRADE, AD PERPENDICULAR PE BC , AB=3 CM, AC=4, AFLATI, BC, AD ,BD SI DC?? plzzz

Answer 1

BC²=AB²+AC²
BC²=3²+4²
BC²=9+16=25
BC=5

AB²=BCxBD
3²=5xBD
BD=9/5

AC²=BCxCD
4²=5xCD
CD=16/5

AB²=AD²+BD²
3²=AD²+(9/5)²
9=AD²+81/25
9x25/25=AD²+81/25
AD²=225/25-81/25
AD²=144/25=12²/5²
AD=12/5

Answer 2

Aplici Pitagora in triunghiul ABC de acolo afli BC:BC^2=AB^2+AC^2
BC^2=3^2+4^2
BC^2=9+16
BC^2=25
BC=5cm
Apoi aplici formula teoremei catetei
AB^2=BC*BD
3^2=5*BD
BD=9/5 cm
AC^2=BC*CD
4^2=5*CD
16=5*CD
CD=16/5 cm
aplici formula inaltimii
AD^2=BD*CD
AD^2=9/5*16/5
AD^2=144/25
AD^2=rad din 144/25
AD=12/5 cm
Asa m-am gandit!Sper sa te ajute!Bafta!