Question

Fie triunghiul ABCdreptunghic in A.Daca AB=6cm BC=10cm calculati AC,sin C,cosC,tgB, ctgB

Answer 1

Prin Pitagora afli AC
BC²=AB²+AC²
100=36+AC²⇒AC²=64⇒AC=8 cm
$sin C=\frac{AB}{BC} = \frac{6}{10} = \frac{3}{5}$
$cos C=\frac{AC}{BC} = \frac{8}{10} = \frac{4}{5}$
$tg B=\frac{AC}{AB} = \frac{8}{6} = \frac{4}{3}$
$ctgB= \frac{AC}{AB} = \frac{3}{4}$