Question

fie un nr natural de 3 cifre ABC (in baza10)
scrieti in ordine crescatoare numerele : 2 , ab (in bz 10) / 5 , abc(in bz 10) / 50​

Answer 1

Răspuns:

$2\leq \frac{\frac{}{ab}}{5}\leq \frac{\frac{}{abc}}{50}$

Explicație pas cu pas:

a ≥ 1  ⇒  2a ≥ 2

$\frac{\frac{}{ab}}{5} =\frac{10a+b}{5} =2a+\frac{b}{5} \geq 2a$

$\frac{\frac{}{abc}}{50} =\frac{100a+10b+c}{50} =2a+\frac{b}{5} +\frac{c}{50} \geq 2a+\frac{b}{5}$