Question

Fie un triunghi oarecare cu laturile BC = a, AC = b, AB = c unde
a, b, c sunt valorile necunoscutelor din exerciţiile de mai jos:

121 x 3 + a + 484 : 2 = 999 – 273

(7 x 3 + 17 x 3) : 9 x (612 : 4- b) = 96

(c: 4+ 26 x 3): 10 - 195 : 3 =75​

Answer 1

Răspuns:

121x3+BC+484:2=999-273

363+BC+242=726

363+BC=726-242

363+BC=484

BC=484-363

BC=121

(7×3+17×3):9×(612:4-b)=96

(21+51):9×(153-AC)=96

72:9×(152-AC)=96

8×(152-AC)=96

152-AC= 96:8

152-AC=12

AC=152-12

AC=140

(c:4+26×3):10-195:3=75

(AB:4+26×3):10-195=75×3

(AB:4+26×3):10-195=225

(AB:4+26×3):10=225+195

(AB:4+26×3):10=420

(AB:4+26×3)=420×10

AB:4+26×3=4200

AB:4+26=4200:3

AB:4+26=1400

AB:4=1400-26

AB:4=1374

AB=1374×4

AB=5396