Question

Fie unghiurile AOB si BOC adiacente.Stiind ca:
a) m(∡AOB)=32°15' si m(∡BOC)=2×m(∡AOB),aflati m(∡AOC);
b)m(∡AOB)=48° si m(∡BOC)=1/3 m(∡AOB),aflati m(∡AOC);
c)m(∡AOC)=100° si m(∡BOC)=40°18',aflati m(∡AOB)'
d)m(∡AOC)=72° si m(∡AOB)=2× m(∡BOC).aflati m(∡AOB) si m(∡BOC);
e)m(∡AOC)=75° si m(∡AOB)=2/3 m(∡BOC),aflati m(∡AOB) si m(∡BOC).
Va rog frumos!

Answer 1

a)<BPC=2·32*15` =64*30`  (2·15`=30`,2·32=64)
b)<BOC=48:3=16g>
<AOC=<AOB+<BOC=48+16=64*
c) <AOB=<AOC-<BOC=100-40*18`=99*60`-40*18`=59*42`
d)<BOC=x* <AOB=2x*=>
AOC=2x+x=3x  =>
72*=3x  x=72:3=24*  <AOB=24*  <AOC=2*24=48*
e) <BOC=x , <AOB=2x/3=>
<AOC=2x/3+x
75=5x/3  =>5x=225*  x=225:5=45*  => <BOC=45*  =>,AOB=2/3·45=30*