Question

Fie x=1, y=2 si z=3. Evaluati expresiile:
a)x+2*y+3*z
b)(1+x+y-2)*z
c)x*y+y*(-z)
d)not (x+y+z > 0)
e)x*y < y+z
f)(x > y) or (2*x < y+z)

Answer 1

a) 1+2*2+3*3= 1+4+9=14

b) (1+1+2-2)*3= 2*3=6

c) 1*2+2*(-3)= 2+(-6)= -4

d) not (1+2+3>0) = not(6>0) = not (true) = false

e) 1*2 < 2+3 = 2<5 = true

f) (1>2) or (2*1<2+3) = false or (2<5) = false or true = true