Question

Fie x diferit de 0, calculati

Answer 1

   
[tex]\displaystyle\\ 0,\!(3)x\cdot (-2x)^2 + 0,\!(2) \cdot (-3x^2)\cdot \Big(-\frac{1}{3} \cdot x\Big) =\\\\ =\frac{3}{9} \cdot x\cdot 4x^2 + \frac{2}{9} \cdot (-3x^2)\cdot \Big(\frac{-1}{3} \cdot x\Big) =\\\\ =\frac{1}{3} \cdot x\cdot 4x^2 + \frac{2}{9} \cdot (-3x^2)\cdot \Big(\frac{-x}{3}\Big) =\\\\ =\frac{x\cdot 4x^2}{3} + \frac{2}{9} \cdot \Big(\frac{(-3x^2)\cdot (-x)}{3}\Big) =\\\\ =\frac{4x^3}{3} + \frac{2}{9} \cdot \Big(\frac{3x^3}{3}\Big) =\\\\ [/tex]


[tex]\displaystyle\\ =\frac{4x^3}{3} + \frac{2}{9} \cdot x^3 =~~~~~\text{Aducem la acelasi numitor.}\\\\ =\frac{3\cdot4x^3}{3\cdot3} + \frac{2x^3}{9}=\frac{12x^3}{9} + \frac{2x^3}{9}= \frac{12x^3+2x^3}{9} =\boxed{\bf \frac{14x^3}{9}} [/tex]