Question

folosind masa molara calculati compozitia procentuală următoarele substanţe: CaCO4;CaO;CH4;MgCl2 .si rezolvarea daca se poate

Answer 1

M=masa moleculara,g/mol
MCaCO3=40+12+48=100g/mol
%Ca=mCa/M*100=40/100*100=40
%C=mC/M*100=12/100*100=12
%O=48
MCaO=40+16=56g/mol
%Ca=mCa/M*100=40/56*100=71.42
%O=mO/M*100=16/56*100=28.57
MCH4=12+4=16g/mol
%C=mC/M*100=12/16*100=75
%O=25
MMgCl2=24+2*35.5=95g/mol
%Mg=mMg/M*100=24/95*100=25.26
%Cl=mCl/M*100=71/95*100=74.73