Question

Folosind masa moleculara ,calculati compozitiaa procentuala a urmatoarelor substante:
a. CaCo3 b.CaO c. CH4 d. Mg CI2

Answer 1

a) M(CaCO3)=1*40+1*12+3*16=100
C(Ca)=40*100%/100=40%
C(C)=12*100%/100=12%
C(O)=3*16*100%/100=48%
b) M(CaO)=40+16=56
C(Ca)=40*100%/56=71,43%
C(O)=16*100%/56=28,57%
c) M(CH4)=1*12+4*1=16
C(C)=12*100%/16=75%
C(H)=4*1*100%/16=25%
d) M(MgCl2)=1*24+2*35,5=95
C(Mg)=24*100%/95=25,26
C(Cl)=2*35,5*100%/95=74,74
C este concentratia procentuala