Question

Folosind metoda mersului invers aflați numărul natural x din egalitatea: [(x-8):2^2+3]•2=22

Answer 1

[ ( x - 8 ) : 2^2 + 3 ] × 2 = 22
[ ( x - 8 ) : 4 + 3 ] × 2 = 22
[ ( x - 8 ) : 4 + 3 ] = 22 : 2
[ ( x - 8 ) : 4 + 3 ] = 11
( x - 8 ) : 4 = 11 - 3
( x - 8 ) : 4 = 8
x - 8 = 8 × 4
x - 8 = 32
x = 32 + 8
x = 40

Answer 2

[( x - 8 ) : 2 ^2 + 3 ] × 2 = 22
[( x - 8 ) : 4 + 3 ] × 2 = 22
[( x - 8 ) : 4 ]+ 3 = 22 : 2
[( x - 8 ) : 4] + 3 = 11
(x - 8 ) : 4 = 11 - 3
(x - 8 ) : 4 = 8
x-8 = 8 × 4
x -8 = 32
x = 32 + 8
x = 40
[ ( 40 - 8 ) : 4 + 3 ] × 2 = 22