Question

forma cea mai simpla a fractiei
$( \sqrt{7} - \sqrt{2}) {}^{2} + \sqrt{56}$
supra
$\sqrt{27}$
este......
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Answer 1

$\frac{(\sqrt{7} - \sqrt{2})^{2} + \sqrt{56}}{\sqrt{27} } = \frac{7-2\sqrt{14} + 2 + 2\sqrt{14}}{\sqrt{27} } = \frac{9}{3\sqrt{3} } =  \frac{3}{\sqrt{3} } =  \sqrt{3}$