Question

formati ecuatia de gradul al 2 lea daca x1=2+ radical 2 si x2=2- radical 2​

Answer 1

Bună! ⭐

_________

x₁; x₂ ∈ R

S=x₁+x₂

P=x₁*x₂

x²-Sx+P=0

__________

$\left \{ {x_{1}=2+\sqrt{2} } \atop {x_{2}=2-\sqrt{2} }} \right. => S=4, P=2$

$S=2+\sqrt{2} +2-\sqrt{2} =2+2=4$

$P=(2+\sqrt{2} )(2-\sqrt{2} )=2^{2} -(\sqrt{2})^{2} =4-2=2$

x²-Sx+P ⇒ x²-4x+2