Question

Formula chimica;Raportul de masa;Rapotul atomic;Raport procentual​

Answer 1

Răspuns:

a)

CO2

RAPORT ATOMIC =C:O=1:2

RAPORT DE MASA=C:O=12:32=3:8

COMPOZITIE PROCENTUALA

MCO2=AC+2×AO=12+2×16=44g/mol

28gCO2.......12gC.......44gO

100gCO2......xgC.........ygO

x=100×12/44=calculează

y=100×16/44=calculează

b) Ca(OH)2

RAPORT ATOMIC =Ca:O:H=1:2:2

RAPORT DE MASA=Ca:O:H=40:32:2=20:16:1

COMPOZITIE PROCENTUALA

MCa(OH)2=40+2×16+2×1=74g/mol

74gCa(OH)2.............40gCa.................32gO.......2gH

100gCa(OH)2..........xgCa......................ygO...........zgH

x=100×40/74=calculeaza

y=100×32/74=calculeaza

z= 100×2/74=calculeaza

c) MgSO4

RAPORT ATOMIC= Mg: S:O=1:1:4

RAPORT DE MASA = Mg:S:O=24:32:64=3:4:8

COMPOZITEI PROCENTUALA

MMgSO4=24+32+4×16=20g/mol

120 gMgSO4............24 g Mg..............32g S.............64 g O

100g.............................xgMg...............................ygS..........zgO

x=100×24/120=calculeaza

y=100×32/120=calculeaza

Z=120×64/120=calculeaza

d) Ca3(PO4)2

RAPORT ATOMIC= Ca: P:O=3:2:8

RAPORT DE MASA  = Ca: P:O=120:62:128=60:31:64

COMPOZITIE PROCENTUALA

MCa3(PO4)2=3×40+2×31+8×16=310g/mol

310g Ca3(PO4)2...................120gCa..............62gP..................128gO

100gCa3(PO4)2.....................xgCa...................ygP....................zgO

x=100×120/310=cacluleaza

y=100×62/310=calculeaza

z=100×128/310=calculeaza

Explicație: