Question

Fosforul se foloseste la producerea chibriturilor si arde in oxigen conform ecuatiei de combinare P+O2->P2O5 Determina masa oxidului de fosfor p2o5 daca in reactie sau consumat 62g fosfor
Urgent va rogg

Answer 1

Mai intai aflam numarul de moli de fosfor (P):

$\displaystyle\nu _P = \frac{m_P}{\mu_P}\\\\m_P=62\:g\\\mu_P=31\:g/mol\\\\\displaystyle\nu _P = \frac{62}{31}=2\:moli$

$\underset{2\:moli}{2P}+\dfrac52O_2 \longrightarrow \underset{x\:moli}{P_2O_5}\\\\\dfrac22=\dfrac1x\implies 1=\dfrac1x\implies x=1\\\\\nu _{P_2O_5}=x=1 mol$

$\mu _{P_2O_5}=2A_P+5A_O=2\cdot31+5\cdot16=62+80=142\:g/mol\\\\m_{P_2O_5}=\mu_{P_2O_5}\cdot\nu_{P_2O_5}=142\cdot1=142\:g$

Raspuns: 142 g de oxid de fosfor