Question

( \frac{3^0*x^{-1}}{x^2})^5:(x^{-2})^14$( \frac{3^0*x^{-1}}{x^2})^5:(x^{-2})^14$

Answer 1

   
$( \frac{3^0*x^{-1}}{x^2})^5:(x^{-2})^{14}= \\ \\ = (x^{-1-2})^{5}: ( x^{-2} )^{14} = \\ \\ =(x^{-3})^{5}: ( x^{-2} )^{14}= \\ \\ = x^{-3*5} : x^{-2*14}= \\ \\ = x^{-15} : x^{-28}= \\ \\ = x^{-15-(-28)}= x^{-15+28}= x^{13}$

Answer 2

$( \frac{1* \frac{1}{x} }{ x^{2} } ) ^{5} : x^{-2} *4 \\ = ( \frac{1}{x}* \frac{1}{ x^{2} } ) ^{5} :x^{-2} *4 \\ = \frac{1}{ x^{3} } : \frac{1}{ x^{2} } * 4 \\ = \frac{1}{ x^{3} } * x^{2} * 4 \\ = \frac{4 x^{2} }{ x^{3} }$