Question

fractii ireductibile 122412/132613

Answer 1

   
[tex]\displaystyle \frac{122412}{132613}~~\text{Verificam daca se simplifica} \\ \\ 122412 = 2^2 \times 3 \times 101^2 \\ 132613 = 13 \times 101^2 \\ \Longrightarrow ~~\text{Fractia se simplifica cu } 101^2 \\ \\ \frac{122412}{132613} = \frac{2^2 \times 3 \times 101^2}{13 \times 101^2} = \frac{2^2 \times 3 }{13}= \frac{4 \times 3}{13}= \boxed{\frac{12}{13}} [/tex]